Frequently asked questions
Dosing: how many grams, how many mg?
All values are approximate estimates using the same formula as the app calculator.
How many grams of flower do I need at 22% THC?
For 12 servings of approx. 10 mg (120 mg total), you need approx. 0.87 g of 22% flower in cannabis butter, or 0.75 g in coconut oil. The calculation accounts for decarboxylation and infusion losses; the percentage is a calculator input, not a substitute for laboratory analysis.
How many mg does 1 g of flower at 22% yield?
Approx. 138 mg in butter, 160 mg in coconut oil and 176 mg in MCT oil. These are estimates for 1 g at 22%, not measured values.
How many grams at 18% or 25%?
For 120 mg total in butter: approx. 1.07 g at 18% or 0.77 g at 25%. A higher percentage means less flower is needed.
How do I calculate the dose per serving?
mg per serving = grams of flower × percentage × 10 × carrier factor ÷ number of servings. The carrier factor includes decarboxylation and infusion losses (butter 0.625, coconut oil 0.725, MCT oil 0.8). The app calculator handles this automatically.
Which fat is suitable?
Cannabinoids are fat-soluble. Butter, coconut oil and MCT oil are suitable carriers. Actual yield also depends on the method and ingredients; the app uses estimated factors. Lecithin is not a carrier on its own — it stabilises the mixture.
Do I need to heat the flower in the oven first?
Activating THCA requires heat (decarboxylation). Raw flower mainly contains the acid form; pre-infused ingredients may already be activated. See the app instructions for temperature and time.
How many mg should beginners consider?
Where consumption is legal: start low, for example approx. 2.5–5 mg, and do not redose too soon. Wait at least 2 hours; effects may take longer to appear. Follow local public-health guidance. Edibles have delayed and longer-lasting effects. Ages 18+ or the higher local legal minimum only; not individual medical advice.
Why are all values approximate?
Actual content depends on the variety, measurement, heat and preparation. We give estimates rather than theoretical maximums — only laboratory analysis can establish an exact value.